Trigonometry
Exercise 11.4 Solutions Exercise 11.4 Solutions From Class X Mathematics textbook by the State Council of Educational Research and Training, Telangana, Hyderabad 1. Evaluate the following: (i) \( (1 + \tan \theta + \sec \theta) (1 + \cot \theta – \csc \theta) \) Let’s expand the expression: \( = 1(1 + \cot \theta – \csc … Read more
Exercise 11.3 Solutions Exercise 11.3 Solutions Class X Mathematics textbook by the State Council of Educational Research and Training, Telangana, Hyderabad 1. Evaluate: (i) \(\frac{\tan 36^\circ}{\cot 54^\circ}\) We know that \(\cot(90^\circ – \theta) = \tan\theta\), so \(\cot 54^\circ = \tan 36^\circ\). Therefore, \(\frac{\tan 36^\circ}{\cot 54^\circ} = \frac{\tan 36^\circ}{\tan 36^\circ} = 1\) (ii) \(\cos 12^\circ – … Read more
Exercise 11.2 Solutions – Class X Mathematics Exercise 11.2 Solutions Class X Mathematics textbook by the State Council of Educational Research and Training, Telangana, Hyderabad 1. Evaluate the following: (i) \(\sin 45^\circ + \cos 45^\circ\) Solution: We know that \(\sin 45^\circ = \frac{1}{\sqrt{2}}\) and \(\cos 45^\circ = \frac{1}{\sqrt{2}}\) \(\sin 45^\circ + \cos 45^\circ = \frac{1}{\sqrt{2}} … Read more
Exercise 11.1 Solutions Exercise 11.1 Solutions 1. In right angle triangle ABC, 8 cm, 15 cm and 17 cm are the lengths of AB, BC and CA respectively. Then, find sin A, cos A and tan A. Diagram description: Right-angled triangle ABC with right angle at B. AB is the side adjacent to angle A … Read more